문제 https://school.programmers.co.kr/learn/courses/30/lessons/42577 My Solution Idea. any, startswith 이용 def solution(phone_book): ''' string 에서 subset 확인 ''' for phone in phone_book: if any(other_phone.startswith(phone) for other_phone in phone_book if other_phone != phone): return False return True 다른 전화부를 비교하는데 오버헤드 발생 Other’s Solution https://school.programmers.co.kr/learn/courses/30/lessons/..

문제 https://school.programmers.co.kr/learn/courses/30/lessons/42576 My Solution Idea 1. remove 사용 def solution(participant, completion): for person in completion: participant.remove(person) return participant[0] list의 remove()는 시간 복잡도가 O(1) ~ O(N) ⇒ 효율성 테스트 통과 불가 Idea 2. dict, counter 사용 from collections import Counter def solution(participant, completion): dict_participant = dict(Counter(partici..